Comments

Show Search Options

Before commenting, read the how to comment guide.

mollytov said:
I'm trying to think of a funny, non-offensive way to make a "steel beams" 9/11 joke but i just now realized that's an oxymoronic thing to do

you will never not offend anyone :)

  • Reply
  • |
  • 2
  • mollytov said:
    I'm trying to think of a funny, non-offensive way to make a "steel beams" 9/11 joke but i just now realized that's an oxymoronic thing to do

    A SECOND WEREWOLF HAS HIT THE TOWERS

  • Reply
  • |
  • 1
  • stuckuplatinwords said:
    Let's say that, based off of Jackie's and Veronica's heights, that this I-beam:

    - is 6 inches wide (i.e. the left-to-right width of each of the flat parts on both sides if the I-beam were resting on the flat parts)
    - is 8 inches high (i.e. the top-to-bottom length/height of the entire I-beam; parallel to the middle part if the beam were resting on the flat parts)
    - has flanges (i.e. the top-to-bottom thickness of the flat parts on both sides if the I-beam were resting on the flat parts) that are each 1 inch thick
    - has a web (i.e. the left-to-right thickness of the flat part in the middle if the I-beam were resting on the flat parts) that's 1 inch thick
    - is 8 feet long
    - is bent/deformed by about 2.5 feet/30 inches

    Additionally, let's assume this I-beam is made out of mild steel, which has a Young's modulus of 200 gigapascals, or 29,010,000 pounds per square inch, since that's usually what I-beams used for construction are made of.

    If we plug those values into this calculator (cross-sectional area of the beam) and this calculator (beam deflection/deformation under stress), that means she's putting 35,000,000 pounds - about 15,875 metric tons - of force on that I-beam to deform it to within the ballpark of 30 inches. For reference, an American WW2 New Orleans-class cruiser weighs somewhere between 10,110 and 12,663 metric tons. Moreover, I deliberately underestimated all those values above except for the Young's modulus and the weight of the New Orleans-class, meaning that the I-beam is probably more durable than I actually did the math for, meaning that she's exerting even more force than that.

    Either way, that means that her thighs can exert more force, as a point load, than the weight of a warship.

    I'm unsure as to what I should do with all this, or what purpose it serves, but I had to do it.

    and here I am thinking yea the mood of the store worker at seaing that is accurate working in retail sucks your soul out

  • Reply
  • |
  • 0
  • stuckuplatinwords said:
    Let's say that, based off of Jackie's and Veronica's heights, that this I-beam:

    - is 6 inches wide (i.e. the left-to-right width of each of the flat parts on both sides if the I-beam were resting on the flat parts)
    - is 8 inches high (i.e. the top-to-bottom length/height of the entire I-beam; parallel to the middle part if the beam were resting on the flat parts)
    - has flanges (i.e. the top-to-bottom thickness of the flat parts on both sides if the I-beam were resting on the flat parts) that are each 1 inch thick
    - has a web (i.e. the left-to-right thickness of the flat part in the middle if the I-beam were resting on the flat parts) that's 1 inch thick
    - is 8 feet long
    - is bent/deformed by about 2.5 feet/30 inches

    Additionally, let's assume this I-beam is made out of mild steel, which has a Young's modulus of 200 gigapascals, or 29,010,000 pounds per square inch, since that's usually what I-beams used for construction are made of.

    If we plug those values into this calculator (cross-sectional area of the beam) and this calculator (beam deflection/deformation under stress), that means she's putting 35,000,000 pounds - about 15,875 metric tons - of force on that I-beam to deform it to within the ballpark of 30 inches. For reference, an American WW2 New Orleans-class cruiser weighs somewhere between 10,110 and 12,663 metric tons. Moreover, I deliberately underestimated all those values above except for the Young's modulus and the weight of the New Orleans-class, meaning that the I-beam is probably more durable than I actually did the math for, meaning that she's exerting even more force than that.

    Either way, that means that her thighs can exert more force, as a point load, than the weight of a warship.

    I'm unsure as to what I should do with all this, or what purpose it serves, but I had to do it.

    thats one hell of a watermellon then~

  • Reply
  • |
  • 1
  • The sword reminds me way too much of Providence from Risk of Rain for some reason

    Either that, or the Doom Slayer

  • Reply
  • |
  • 1
  • coyotebear said:

    Prydr does seem to have bigger tiddy than ever, true




    also, OMG those abs

    I meant it in every single possible way. She looks overall bigger and more imposing as does her sword

  • Reply
  • |
  • 0
  • Aaaa this style is so cute ๐Ÿ˜ญ

    Edit: OH it's Zackary! That explains it! I love how squishy and soft their art is <3

  • Reply
  • |
  • 5
  • alleycat8706 said:
    Aaaa this style is so cute ๐Ÿ˜ญ

    Edit: OH it's Zackary! That explains it! I love how squishy and soft their art is <3

    Yes, not that many artists are really good at conveying a sense of how soft and squishy their characters must be. Meanwhile Zack is doing such a thing left and right.

  • Reply
  • |
  • 0