Nobody would care about his grade in this situation...
in fact, i think some (*caugh*) would even make it worse to get that a chance on extra credit :)

Oh my god, he's... Handsome! xwx

I'd love to pass an oral test on him wink wonk

its obvious he's a math teacher, he wants you to find the length of his shaft and the circumference of his knot.

Shana123 said:
its obvious he's a math teacher, he wants you to find the length of his shaft and the circumference of his knot.

roll for anal circumference

Fenrick said:
Those equations don't follow. a • b and a x b should be the exact same thing.

The math checks out just fine lol.

Assuming 3D vectors, a and b, the square of the minimal quaternion rotation, q2 (q squared), which transforms vector a into vector b through left multiplication, q*a = b, is given as follows:

q2's w, x, y, and z are the real, and three complex coefficients of the quaternion

q2w = ax*bx + ay*by + az*bz
q2x = ay*bz - az*by
q2y = az*bx - ax*bz
q2z = ax*by - ay*bx

the w component is clearly (a dot b)
the xyz components are (a cross b)

In order to get the rotation, q, from the square rotation, q2, we can add 1 and unitize.
This simplifies into q = sqrt(q2) = (q2 + 1)/sqrt(2*(q2w + 1))

From the foregoing, we can conclude that:
1. He has a BIG dick. And
2. He has a BIG knot.

Class dismissed...

AxisAngles said:
The math checks out just fine lol.

Assuming 3D vectors, a and b, the square of the minimal quaternion rotation, q2 (q squared), which transforms vector a into vector b through left multiplication, q*a = b, is given as follows:

q2's w, x, y, and z are the real, and three complex coefficients of the quaternion

q2w = ax*bx + ay*by + az*bz
q2x = ay*bz - az*by
q2y = az*bx - ax*bz
q2z = ax*by - ay*bx

the w component is clearly (a dot b)
the xyz components are (a cross b)

In order to get the rotation, q, from the square rotation, q2, we can add 1 and unitize.
This simplifies into q = sqrt(q2) = (q2 + 1)/sqrt(2*(q2w + 1))

Amazing. Just... wow. Seriously.

I've been a bad boy mister...why don't you teach me a lesson 😘

Desy said:
I've been a bad boy mister...why don't you teach me a lesson 

*cue the cheesy porn music*

AxisAngles said:
The math checks out just fine lol.

Assuming 3D vectors, a and b, the square of the minimal quaternion rotation, q2 (q squared), which transforms vector a into vector b through left multiplication, q*a = b, is given as follows:

q2's w, x, y, and z are the real, and three complex coefficients of the quaternion

q2w = ax*bx + ay*by + az*bz
q2x = ay*bz - az*by
q2y = az*bx - ax*bz
q2z = ax*by - ay*bx

the w component is clearly (a dot b)
the xyz components are (a cross b)

In order to get the rotation, q, from the square rotation, q2, we can add 1 and unitize.
This simplifies into q = sqrt(q2) = (q2 + 1)/sqrt(2*(q2w + 1))

I would rather know the displacement volume if you know what I mean.

Anything is a lollipop if you want it to be.

I've been a bad student, you have to punish me.

DoctorTAR1S said:
Amazing. Just... wow. Seriously.

tru. meanwhile, i failed linear algebra cause i'm stupid af

Telhem said:
I would rather know the displacement volume if you know what I mean.

Don't tempt him. He can probably give you an accurate answer just from this image alone.

hmm interesting..

This picture made me bi.

axisangles said:
The math checks out just fine lol.

Assuming 3D vectors, a and b, the square of the minimal quaternion rotation, q2 (q squared), which transforms vector a into vector b through left multiplication, q*a = b, is given as follows:

q2's w, x, y, and z are the real, and three complex coefficients of the quaternion

q2w = ax*bx + ay*by + az*bz
q2x = ay*bz - az*by
q2y = az*bx - ax*bz
q2z = ax*by - ay*bx

the w component is clearly (a dot b)
the xyz components are (a cross b)

In order to get the rotation, q, from the square rotation, q2, we can add 1 and unitize.
This simplifies into q = sqrt(q2) = (q2 + 1)/sqrt(2*(q2w + 1))

Neeeeeerd...........👍